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x^2-4x-896=0
a = 1; b = -4; c = -896;
Δ = b2-4ac
Δ = -42-4·1·(-896)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-60}{2*1}=\frac{-56}{2} =-28 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+60}{2*1}=\frac{64}{2} =32 $
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